document.write( "Question 1124436: I need help with this question: If angle a and angle b are complementary and the measure of angle a is x-8 and measure of angle b is 3 times the quantity of x+2/3 then find the supplement of angle B. \n" ); document.write( "
Algebra.Com's Answer #740736 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "recall:\r
\n" ); document.write( "\n" ); document.write( "Two angles are complementary when they add up to \"90\" degrees (a right angle).\r
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\n" ); document.write( "\n" ); document.write( "Two angles are supplementary when they add up to \"180\" degrees.\r
\n" ); document.write( "\n" ); document.write( "given:\r
\n" ); document.write( "\n" ); document.write( "the measure of angle \"a=+x-8\", and
\n" ); document.write( "measure of angle \"b=+3+%28x%2B2%2F3%29\"\r
\n" ); document.write( "\n" ); document.write( "\"x-8%2B+3+%28x%2B2%2F3%29=90\"\r
\n" ); document.write( "\n" ); document.write( "\"x-8%2B+3x%2Bcross%283%29%282%2Fcross%283%29%29=90\"\r
\n" ); document.write( "\n" ); document.write( "\"x-8%2B+3x%2B2=90\"\r
\n" ); document.write( "\n" ); document.write( "\"4x-6=90\"\r
\n" ); document.write( "\n" ); document.write( "\"4x=90%2B6\"\r
\n" ); document.write( "\n" ); document.write( "\"4x=96\"\r
\n" ); document.write( "\n" ); document.write( "\"x=96%2F4\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28x=24%29\"\r
\n" ); document.write( "\n" ); document.write( "then\r
\n" ); document.write( "\n" ); document.write( "\"a=+x-8\"->\"a=+24-8\"->\"highlight%28a=16%29\"\r
\n" ); document.write( "\n" ); document.write( "\"b=+3+%28x%2B2%2F3%29\"->\"b=+3+%2824%2B2%2F3%29\"->\"b=+72%2B3%282%2F3%29\"->\"b=+72%2B2\"->\"highlight%28b=+74%29\"\r
\n" ); document.write( "\n" ); document.write( "then, the supplement of angle \"b\" will be \"180-b=180-74=highlight%28106%29\"\r
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