document.write( "Question 1124409: The cost function for a certain company is
\n" ); document.write( "C = 50x + 600 and the revenue is given by R = 100x − 0.5x2.
\n" ); document.write( " Recall that profit is revenue minus cost. Set up a quadratic equation and find two values of x (production level) that will create a profit of $600.
\n" ); document.write( "

Algebra.Com's Answer #740723 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "\"C+=+50x+%2B+600\" and the revenue is given by \"R+=+100x+-0.5x%5E2\".\r
\n" ); document.write( "\n" ); document.write( " Recall that profit is revenue minus cost.\r
\n" ); document.write( "\n" ); document.write( "\"P=R-C\"\r
\n" ); document.write( "\n" ); document.write( "\"P=100x+-0.5x%5E2-%2850x+%2B+600%29\"\r
\n" ); document.write( "\n" ); document.write( "\"P=100x+-0.5x%5E2-50x+-+600\"\r
\n" ); document.write( "\n" ); document.write( "\"P=-0.5x%5E2%2B50x++-+600\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "find two values of \"x+\"(production level) that will create a profit of $\"600\":\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"600=-0.5x%5E2%2B50x++-+600\"\r
\n" ); document.write( "\n" ); document.write( "\"0.5x%5E2-50x%2B600%2B600=0+\"\r
\n" ); document.write( "\n" ); document.write( "\"0.5x%5E2-50x%2B1200=0+\"\r
\n" ); document.write( "\n" ); document.write( "\"0.5%28x%5E2-100x%2B2400%29=0+\"\r
\n" ); document.write( "\n" ); document.write( "\"0.5%28x%5E2-40x-60x%2B2400%29=0+\"\r
\n" ); document.write( "\n" ); document.write( "\"0.5%28%28x%5E2-40x%29-%2860x-2400%29%29=0+\"\r
\n" ); document.write( "\n" ); document.write( "\"0.5%28x%28x-40%29-60%28x-40%29%29=0+\"\r
\n" ); document.write( "\n" ); document.write( "\"0.5+%28x+-+60%29+%28x+-+40%29+=+0+\"\r
\n" ); document.write( "\n" ); document.write( "since \"0.5%3C%3E0\", equation will be zero if \"%28x+-+60%29++=+0+\" or \"++%28x+-+40%29+=+0+\"\r
\n" ); document.write( "\n" ); document.write( "if \"%28x+-+60%29++=+0+\"->\"x=60\"
\n" ); document.write( "if \"++%28x+-+40%29+=+0+\"->\"x=40\"\r
\n" ); document.write( "\n" ); document.write( "so, the values of x (production level) that will create a profit of $\"600\" are \"x=40\" and \"x=60\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );