document.write( "Question 1124380: Hi, please help me solve this question:\r
\n" ); document.write( "\n" ); document.write( "SCRAP is a 5-digit number. The digits S,C,R,A, and P are used in these addition problems: A+A+A=CA and RS+RS+RS= PR\r
\n" ); document.write( "\n" ); document.write( "What number is scrap?
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Algebra.Com's Answer #740716 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "In order to solve this, one has to assume that two different letters cannot stand for the same digit.\r
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\n" ); document.write( "\n" ); document.write( "Given that, we first look at A + A + A = CA, which is to say 3*A = CA.\r
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\n" ); document.write( "\n" ); document.write( "Since the result is a two digit number, A must be larger than 3 because 3 times 3 is only 9. Also, A must be 9 or smaller because 9 is the largest single digit. Then looking at a multiplication table in the 3s column where the multiplier is 4 or larger, the only result where the second digit is the same as the multiplier is 3 X 5 = 15. Therefore A is 5 and C is 1.\r
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\n" ); document.write( "\n" ); document.write( "Since 3 times RS is also a 2 digit number with two different digits, RS must be 32 or less because it can't be 33 and anything larger would have a result of three digits, and the smallest 2 digit number is 10 so it must be at least that. We want to find a multiple of 3 where the tens digit of the multiplier is the same as the ones digit of the product.\r
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\n" ); document.write( "\n" ); document.write( "For multipliers with 1 as a tens digit, the only multiplier that qualifies is 17: 3 X 17 = 51. For multipliers with 2 as a tens digit, the only multiplier that qualifies is 24: 3 X 24 = 72. And for multipliers with 3 as a tens digit, the qualifier is 31: 3 X 31 = 93.\r
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\n" ); document.write( "\n" ); document.write( "But we have already identified C = 1, so 17 and 31 are disqualified, so RS is 24 and PR is 72.\r
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\n" ); document.write( "\n" ); document.write( "SCRAP = 41257
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\n" ); document.write( "John
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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