document.write( "Question 1124281: Wayne invested $9000, part at 9%/annum and the remainder at 8%/annum. After one year the total
\n" ); document.write( "interest from these investments was $750. How much was invested at 9%? \n" ); document.write( "
Algebra.Com's Answer #740652 by ikleyn(52781)\"\" \"About 
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document.write( "0.09*x + 0.08*(9000-x) = 750,\r\n" );
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document.write( "0.09x + 0.08*9000 - 0.08x = 750\r\n" );
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document.write( "(0.09 - 0.08)*x = 750 - 0.08*9000\r\n" );
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document.write( "x = \"%28750+-+0.08%2A9000%29%2F%280.09+-+0.08%29\" = 3000.\r\n" );
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document.write( "Answer.  $3000 was invested at 9%.\r\n" );
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