document.write( "Question 101854This question is from textbook Beginning Algebra
\n" ); document.write( ": The sum of three times a number and 7 more than the number is the same as the difference between -11 and twice the number. Find the number. \n" ); document.write( "
Algebra.Com's Answer #74052 by stanbon(75887)\"\" \"About 
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The sum of three times a number and 7 more than the number is the same as the difference between -11 and twice the number. Find the number.
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\n" ); document.write( "Let the number be \"x\".
\n" ); document.write( "EQUATION:
\n" ); document.write( "3x+(x+7) = -11-2x
\n" ); document.write( "4x+7 = -11-2x
\n" ); document.write( "6x = -18
\n" ); document.write( "x = -3
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\n" ); document.write( "If you interpret \"difference between -11 and twice the number\" as 2x-(-11)
\n" ); document.write( "you get the following:
\n" ); document.write( "3x+(x+7) = 2x--11
\n" ); document.write( "4x+7 = 2x+11
\n" ); document.write( "2x = 4
\n" ); document.write( "x = 2
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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