document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1124154>Question 1124154</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of three numbers is 14.  The sum of twice the first&#8203; number, 4 times the second&#8203; number, and 5 times the third number is 62. The difference between 4 times the first number and the second number is negative 1.  Find the three numbers.\r<BR>\n" );
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document.write( "first&#8203; number:\r<BR>\n" );
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document.write( "second&#8203; number: \r<BR>\n" );
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document.write( "third&#8203; number:\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #740514 by </B><A HREF=/tutors/aboutme.mpl?userid=ikleyn><B>ikleyn(52798)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ikleyn><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ikleyn><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=740514\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .<BR>\n" );
document.write( "Just solved at the link\r<BR>\n" );
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document.write( "https://www.algebra.com/algebra/homework/Linear-equations/Linear-equations.faq.question.1124084.html\r<BR>\n" );
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