document.write( "Question 1124069: Shelias age is two years more than twice Nicole’s age. The sum of their ages is the same as Steve’s age. If Steve’s age is ten years less than five times Nicole’s age, find the age of each. \n" ); document.write( "

Algebra.Com's Answer #740424 by josmiceli(19441) $\"\"$ $\"About$

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Let $\"+a+\"$ = Shelia’s age now
\n" ); document.write( "Let $\"+b+\"$ = Nicole’s age now
\n" ); document.write( "Let $\"+c+\"$ = Steve’s age now
\n" ); document.write( "———————————————-
\n" ); document.write( "(1) $\"+a+=+2b+%2B+2+\"$
\n" ); document.write( "(2) $\"+a+%2B+b+=+c+\"$
\n" ); document.write( "(3) $\"+c+=+5b+-+10+\"$
\n" ); document.write( "————————————
\n" ); document.write( "Plug (2) into (3)
\n" ); document.write( "(3) $\"+a+%2B+b+=+5b+-+10+\"$
\n" ); document.write( "(3) $\"+a+=+4b+-+10+\"$
\n" ); document.write( "Plug (3) into (1)
\n" ); document.write( "(1) $\"+4b+-+10+=+2b+%2B+2+\"$
\n" ); document.write( "(1) $\"+2b+-+5+=+b+%2B+1+\"$
\n" ); document.write( "(1) $\"+b+=+6+\"$
\n" ); document.write( "And
\n" ); document.write( "(1) $\"+a+=+2%2A6+%2B+2+\"$
\n" ); document.write( "(1) $\"+a+=+14+\"$
\n" ); document.write( "And
\n" ); document.write( "(3) $\"+c+=+5%2A6+-+10+\"$
\n" ); document.write( "(3) $\"+c+=+20+\"$
\n" ); document.write( "———————————
\n" ); document.write( "Check:
\n" ); document.write( "(2) $\"+14+%2B+6+=+20+\"$
\n" ); document.write( "OK
\n" ); document.write( "Shelia is 14
\n" ); document.write( "Nicole is 6
\n" ); document.write( "Steve is 20\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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