document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=101802>Question 101802</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A total of $9500 is deposited into two simple interest accounts. On one account the annual simple interest rate is 10% on the second account the annual simple interest rate is 11%. How much should be invested in the 11% account so that the total annual interest earned is $1005? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #74042 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=74042\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A total of $9500 is deposited into two simple interest accounts. On one account the annual simple interest rate is 10% on the second account the annual simple interest rate is 11%. How much should be invested in the 11% account so that the total annual interest earned is $1005?<BR>\n" );
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document.write( "\"x\" dollars at 11% gives 0.11x interest<BR>\n" );
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document.write( "\"9500-x\" at 10% gives 0.10(9500-x)= 950-0.10x interest<BR>\n" );
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document.write( "EQUATION:<BR>\n" );
document.write( "interest + interest = 1005 dollars<BR>\n" );
document.write( "0.11x +950-0.10x = 1005<BR>\n" );
document.write( "0.01x = 55<BR>\n" );
document.write( "x = $5500 (amount invested at 11%)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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