document.write( "Question 1123908: A stone is thrown upward with an initial velocity of 15.24 m/s. What will its maximum height be? When will it strike the ground? Where will it be in 1.30 s? \r
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Algebra.Com's Answer #740412 by ankor@dixie-net.com(22740)\"\" \"About 
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A stone is thrown upward with an initial velocity of 15.24 m/s.
\n" ); document.write( " What will its maximum height be?
\n" ); document.write( ":
\n" ); document.write( "Using -4.9 m/sec as the force of gravity
\n" ); document.write( "h = -4.9x^2 + 15.24x
\n" ); document.write( "Max height occurs at the axis of symmetry x=-b/(2a), a = -4.9, b=15.24
\n" ); document.write( "x = \"%28-15.24%29%2F%282%28-4.9%29%29\"
\n" ); document.write( "x = 1.555 sec it will be max height
\n" ); document.write( "Find the actual height
\n" ); document.write( "h = -4.9(1.555^2) + 15.24(1.555)
\n" ); document.write( "h = -11,848 + 23.698
\n" ); document.write( "h = +11.7 meter is max height
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\n" ); document.write( "When will it strike the ground?
\n" ); document.write( "It strikes the ground when x=0
\n" ); document.write( "-4.9x^2 + 15.24x = 0
\n" ); document.write( "Factor out x
\n" ); document.write( "x(-4.9x + 15.24)
\n" ); document.write( "two solutions
\n" ); document.write( "x = 0 initial position
\n" ); document.write( "and
\n" ); document.write( "-4.9x = -15.24
\n" ); document.write( "x = -15.24/-4.9
\n" ); document.write( "x = 3.11 sec to hit the ground
\n" ); document.write( ":
\n" ); document.write( " Where will it be in 1.30 s?
\n" ); document.write( "x=1.3
\n" ); document.write( "h = -4.9(1.3^2) + 15.24(1.3)
\n" ); document.write( "I'll let you calculate this \n" ); document.write( "
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