document.write( "Question 1124019: A merchant has coffee worth $20 a pound that she wishes to mix with 90 pounds of coffee worth $60 a pound to get a mixture that she will sell for $50 a pound. How many pounds (lb) of the $20 coffee should be used? \n" ); document.write( "

Algebra.Com's Answer #740393 by josmiceli(19441) $\"\"$ $\"About$

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Let $\"+x+\"$ = pounds of $20 coffee needed
\n" ); document.write( "ЧЧЧЧЧЧЧЧ-
\n" ); document.write( " $\"+%28+20x+%2B+60%2A90+%29+%2F+%28+x+%2B+90+%29+=+50+\"$
\n" ); document.write( " $\"+20x+%2B+5400+=+50%2A%28+x+%2B+90+%29+\"$
\n" ); document.write( " $\"+20x+%2B+5400+=+50x+%2B+4500+\"$
\n" ); document.write( " $\"+30x+=+900+\"$
\n" ); document.write( " $\"+x+=+30+\"$
\n" ); document.write( "30 pounds of the $20/lb coffee are needed
\n" ); document.write( "ЧЧЧЧЧЧЧ-
\n" ); document.write( "Check:
\n" ); document.write( " $\"+%28+20%2A30+%2B+60%2A90+%29+%2F+%28+30+%2B+90+%29+=+50+\"$
\n" ); document.write( " $\"+6000+%2F+120+=+50+\"$
\n" ); document.write( " $\"+50+=+50+\"$
\n" ); document.write( "OK
\n" ); document.write( " \n" ); document.write( "

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