document.write( "Question 1123946: In △ABC the angle bisectors drawn from vertices A and B intersect at point D. Find ∠ADB if:
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Algebra.Com's Answer #740315 by ikleyn(52814) $\"\"$ $\"About$

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document.write( "    < ADB = 180° - (half of < A + half of < B)     (1)    (as the sum of interior angles of the triangle ABD)\r\n" );
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document.write( "From the other side\r\n" );
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document.write( "      < A + < B + < C = 180°  ====>  half of < A + half of < B = 90° - half < C.\r\n" );
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document.write( "Therefore, you can continue (1) in this way :\r\n" );
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document.write( "    < ADB = 180° - (half of < A + half of < B) = 180° - (90° - half < C) = 90° + half < C.\r\n" );
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document.write( "Or, in terms of  ,    and  \r\n" );
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document.write( "    < ADB =  = .\r\n" );
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