document.write( "Question 1123912: Please help. Thankyou.
\n" ); document.write( "A girl throws a ball vertically upward with a speed of 6.10 m/s from the roof of a building 18.29m high. a.) How long will it take the ball to reach the ground? b.) What will its speed be when it reaches the ground?
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Algebra.Com's Answer #740300 by Alan3354(69443)\"\" \"About 
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A girl throws a ball vertically upward with a speed of 6.10 m/s from the roof of a building 18.29m high. a.) How long will it take the ball to reach the ground? b.) What will its speed be when it reaches the ground?
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\n" ); document.write( "You didn't supply the equation or function for the ball's position.
\n" ); document.write( "9.8 m/sec/sec is commonly used on Earth in metric units. Sometimes
\n" ); document.write( " 10 m/sec/sec is used.
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\n" ); document.write( "9.8 is closer to reality.
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\n" ); document.write( "h(t) = -4.9t^2 + vo*t + h where vo is the upward speed at launch (not velocity) and h is the launch height.
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\n" ); document.write( "a.) How long will it take the ball to reach the ground?
\n" ); document.write( "h(t) = -4.9t^2 + vo*t + h
\n" ); document.write( "h(t) = -4.9t^2 + 6.1*t + 18.29
\n" ); document.write( "-4.9t^2 + 6.1*t + 18.29 = 0 at impact
\n" ); document.write( "Solve for t (ignore the negative solution).
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\n" ); document.write( "b.) What will its speed be when it reaches the ground?
\n" ); document.write( "Speed is the 1st derivative of position.
\n" ); document.write( "h'(t) = -9.8t + 6.1
\n" ); document.write( "Use the value for t from part a.
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