document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1123771>Question 1123771</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Part of the proceeds from a garage sale was $410 worth of $10 and $20 bills. If there were 2 more $10 bills than $20 bills, find the number of each denomination. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #740277 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=740277\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Here is a solution using logical reasoning that uses virtually the same calculations as the formal algebraic solution shown by the other tutor.<br><BR>\n" );
document.write( "(1) First count the two \"extra\" $10 bills.  That leaves equal numbers of $10 and $20 bills, with a total value of $390.<br><BR>\n" );
document.write( "(2) Think of the remaining bills in groups of one $10 bill and one $20 bill.  The value of one $10 bill and one $20 bill is $30.<br><BR>\n" );
document.write( "(3) The number of groups, each worth $30, required to make the remaining $390 of the total is 390/30 = 13.<br><BR>\n" );
document.write( "So the number of $20 bills is 13; and the number of $10 bills is 13+2 = 15. </SPAN>\n" );
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