document.write( "Question 1123771: Part of the proceeds from a garage sale was $410 worth of $10 and $20 bills. If there were 2 more $10 bills than $20 bills, find the number of each denomination. \n" ); document.write( "

Algebra.Com's Answer #740267 by ikleyn(52786) $\"\"$ $\"About$

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document.write( "Let x be the number of the $20 dollars bills.\r\n" );
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document.write( "Then the number of the $10 dollars bills is (x+2), according to the condition.\r\n" );
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document.write( "The money equation is\r\n" );
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document.write( "    20x + 10*(x+2) = 410\r\n" );
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document.write( "Simplify and solve for x.  \r\n" );
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document.write( "    20x + 10x + 20 = 410\r\n" );
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document.write( "    30x = 410-20 = 390  ====>  x =  = 13.\r\n" );
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document.write( "Answer.  13 of the $20-dollars bills and 13+2 = 15  of the $10-dollars bills.\r\n" );
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document.write( "Check.   20*13 + 10*15 = 410 dollars.   ! Correct !\r\n" );
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