document.write( "Question 1123884: Find the largest angle of a triangle where the larger is 20° greater than the smallest and the largest is twice the smallest angle. \n" ); document.write( "
Algebra.Com's Answer #740254 by MathLover1(20849)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "let’s the largest angle be \"alpha\", the larger \"beta\", and the smallest angle \"gamma\"\r
\n" ); document.write( "\n" ); document.write( "the sum is: \"alpha%2Bbeta%2Bgamma=180\"...............eq.1
\n" ); document.write( "if the larger is \"20\"° greater than the smallest, we have\r
\n" ); document.write( "\n" ); document.write( "\"beta=gamma+%2B20\"....eq.2\r
\n" ); document.write( "\n" ); document.write( "if the largest is twice the smallest angle, we have \r
\n" ); document.write( "\n" ); document.write( "\"alpha=2gamma\"...............eq.3\r
\n" ); document.write( "\n" ); document.write( "go to
\n" ); document.write( "\"alpha%2Bbeta%2Bgamma=180\"...............eq.1, substitute \"beta\" and \"alpha\" from eq.1 and eq.3\r
\n" ); document.write( "\n" ); document.write( "\"2gamma%2Bgamma+%2B20%2Bgamma=180\"....solve for \"gamma\"\r
\n" ); document.write( "\n" ); document.write( "\"4gamma+=180-20\"\r
\n" ); document.write( "\n" ); document.write( "\"4gamma+=160\"\r
\n" ); document.write( "\n" ); document.write( "\"gamma+=160%2F4\"\r
\n" ); document.write( "\n" ); document.write( "\"gamma+=40\"°\r
\n" ); document.write( "\n" ); document.write( "go to \"beta=gamma+%2B20\"....eq.2, plug in \"gamma\"\r
\n" ); document.write( "\n" ); document.write( "\"beta=40+%2B20\"\r
\n" ); document.write( "\n" ); document.write( "\"beta=60\"°\r
\n" ); document.write( "\n" ); document.write( "go to \"alpha=2gamma\"...............eq.3, plug in \"gamma\"\r
\n" ); document.write( "\n" ); document.write( "\"alpha=2%2A40\"\r
\n" ); document.write( "\n" ); document.write( "\"alpha=80\"°\r
\n" ); document.write( "\n" ); document.write( "so, the largest angle of a triangle is \"80\"°\r
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