document.write( "Question 1123859: Two years ago Sam was two thirds of Pam's age in three years Sam will be three fourths of Pam's age 20years the sum of their age is 69 has old is sam \n" ); document.write( "
Algebra.Com's Answer #740235 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! let s = Sam's present age \n" ); document.write( "let p = Pam's \n" ); document.write( ": \n" ); document.write( "Write an equation for each statement, simplify \n" ); document.write( ": \n" ); document.write( "Two years ago Sam was two thirds of Pam's age \n" ); document.write( "s - 2 = \n" ); document.write( "multiply both sides by 3 \n" ); document.write( "3(s-2) = 2(p-2) \n" ); document.write( "distribute \n" ); document.write( "3s - 6 = 2p - 4 \n" ); document.write( "3s - 2p = -4 + 6 \n" ); document.write( "3s - 2p = 2 \n" ); document.write( ": \n" ); document.write( "in three years Sam will be three fourths of Pam's age \n" ); document.write( "s + 3 = \n" ); document.write( "multiply both sides by 4 \n" ); document.write( "4(s+3) = 3(p+3) \n" ); document.write( "4s + 12 = 3p + 9 \n" ); document.write( "4s - 3p = 9 - 12 \n" ); document.write( "4s - 3p = -3 \n" ); document.write( "Use elimination with these two equations. Multiply the 1st equation by 3 and the 2nd equation by 2 \n" ); document.write( "9s - 6p = 6 \n" ); document.write( "8s - 6p = -6 \n" ); document.write( "----------------subtraction eliminates p, find s \n" ); document.write( "s + 0 = 12 \n" ); document.write( "s = 12 yrs is Sam's present age \n" ); document.write( "Find p \n" ); document.write( "3(12) - 2p = 2 \n" ); document.write( "-2p = 2 - 36 \n" ); document.write( "-2p = -34 \n" ); document.write( "p = -34/-2 \n" ); document.write( "p = 17 yrs is Pam's present age \n" ); document.write( "; \n" ); document.write( ";\r \n" ); document.write( "\n" ); document.write( "Not sure what this means!! \n" ); document.write( " \"20years the sum of their age is 69 has old is sam \" \n" ); document.write( " |