document.write( "Question 1123854: I have three zeros 3-3i,3+3i, and 3. I am having trouble factoring. I am missing something in the factoring that will get me the right equation. This is what I have so far (x-(3-3i))(x-(3+3i))(x-3). (x-(3-3i))(3+3i)) should factor out to x^2-6x+10 I keep getting x^2-2x+18. The final equation should be x^3-9x^2+28x-30. Could you please assist me with this by working out the factoring to see where I am going wrong.
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document.write( "Thanks \n" );
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Algebra.Com's Answer #740230 by MathLover1(20850)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "zeros: \n" ); document.write( "\n" ); document.write( "to find equation, use product of factors\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |