document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1123850>Question 1123850</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many liters each of a <BR>\n" );
document.write( "25%<BR>\n" );
document.write( "acid solution and a <BR>\n" );
document.write( "85%<BR>\n" );
document.write( "acid solution must be used to produce <BR>\n" );
document.write( "80<BR>\n" );
document.write( "liters of a <BR>\n" );
document.write( "40%<BR>\n" );
document.write( "acid solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #740229 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=740229\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x stand for the number of liters of the 25% solution<BR>\n" );
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document.write( "let y stand for the number of liters of the 85% solution<BR>\n" );
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document.write( "x + y = 80, therefore<BR>\n" );
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document.write( "x = (80-y)<BR>\n" );
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document.write( "0.40 * 80 = 32 liters of acid<BR>\n" );
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document.write( "0.25(80-y) + 0.85y = 32<BR>\n" );
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document.write( "20 - 0.25y + 0.85y = 32<BR>\n" );
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document.write( "0.60y = 12<BR>\n" );
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document.write( "y = 20<BR>\n" );
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document.write( "x = 80 - 20 = 60<BR>\n" );
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document.write( "We need 60 liters of the 25% solution and 20 liters of the 85% solution<BR>\n" );
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document.write( "Note (0.25 * 60) + (0.85 * 20) =  32 liters<BR>\n" );
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