document.write( "Question 1123818: the sum of the ages of three sisters is 64. the age of the oldest is twice the age of the youngest. the ages of the two older sisters is a difference of six years. what is the age of the youngest sister?
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Algebra.Com's Answer #740203 by ikleyn(52797)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( " \r\n" ); document.write( "Let x be the age (in years) of the youngest sister.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Then the oldest sister is 2x years old and the middle age sister is (2x-6) years old.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "The sum is x + 2x + (2x-6), and it is 64.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Your equation is\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "x + 2x + (2x-6) = 64,\r\n" ); document.write( "\r\n" ); document.write( "5x = 64 + 6 = 70\r\n" ); document.write( "\r\n" ); document.write( "x = 70/5 = 14.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Answer. The youngest sister is 14 years old; the oldest is 2*14 = 28 years; the middle age sister is 28-6 = 22 years old.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Check. 14 + 28 + 22 = 64. ! Correct !\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( "Solved.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "================\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The lesson to learn from my solution is THIS :\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( " This problem is to be sold using one unknown and one equation.\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |