document.write( "Question 1123733: Karen and David set out from home at the same time. Karen cycles due north 20km/h and David due east at 15km/h. FInd
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document.write( "a) how far apart they are in 1 hour
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document.write( "b)after how many minutes they are 10km apart
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document.write( "c) the bearing of Karen from David at any time \n" );
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Algebra.Com's Answer #740200 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Karen and David set out from home at the same time. \n" ); document.write( " Karen cycles due north 20km/h and David due east at 15km/h. \n" ); document.write( "FInd \n" ); document.write( "a) how far apart they are in 1 hour \n" ); document.write( "their routes form a right triangle, the hypotenuse is the dist between them \n" ); document.write( "h = \n" ); document.write( "h = 25 km after 1 hr \n" ); document.write( ": \n" ); document.write( "b)after how many minutes they are 10km apart \n" ); document.write( "Change the speeds to km/min \n" ); document.write( "20/60 = .33 km/min \n" ); document.write( "15/60 = .25 km/min \n" ); document.write( "let the t = time in min for them to be 10km apart \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "t^2 = 576 \n" ); document.write( "t = \n" ); document.write( "t = 24 min, they are 10 mi apart \n" ); document.write( ": \n" ); document.write( "c) the bearing of Karen from David at any time \n" ); document.write( "Find the angle (David's position) using the tangent tan(A) = \n" ); document.write( "In relation to true north, 90-53 = 37 degrees, \n" ); document.write( "the Bearing then 360 - 37 = 323 degrees is Karen from David \n" ); document.write( " \n" ); document.write( " |