document.write( "Question 1123833: The length of a rectangle is
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document.write( "4 meters less than twice the width. If the area of the rectangle is
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document.write( "286 square meters, find the dimensions \n" );
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Algebra.Com's Answer #740199 by ikleyn(52786)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( " \r\n" ); document.write( "Let W be the width.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Then the length is L = 2W - 4, and the area is W*L = W*(2W-4).\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Your equation is\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "W*(2W-4) = 286, or\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "W*(W-2) = 143.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "You can solve this quadratic equation using the quadratic formula,\r\n" ); document.write( "\r\n" ); document.write( "or you can mentally find decomposition of the number 143 into the product of two positive integers that differ by 2: 143 = 11*13.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Answer. W = 13 (the width); L = 2*W - 4 = 2*13-4 = 22 (the length).\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Check. 11*18 = 286 square meters. ! Correct !\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |