document.write( "Question 1123813: solve the simultaneous equation: \r
\n" ); document.write( "\n" ); document.write( "1.) log2^x - log2^y =2, log2^(x-2y) =3
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Algebra.Com's Answer #740176 by Alex.33(110)\"\" \"About 
You can put this solution on YOUR website!
Assume that 2 s are the bases of the log, not contained in the expressions.
\n" ); document.write( "(If not please resubmit the qustion with the base specified, in case a bare log x can be recognized to be base e or 10)
\n" ); document.write( "\"log%282%2C+x%2Fy%29=2%2C+log%282%2C+x-2y%29=3\"
\n" ); document.write( "\"x%2Fy=4\"
\n" ); document.write( "\"x-2y=8\"
\n" ); document.write( "\"4y-2y=8\"
\n" ); document.write( "\"y=4\"
\n" ); document.write( "\"x=16\"
\n" ); document.write( "Hope this solves your problem. Thanks!
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