document.write( "Question 1123747: A man travels 180km from his farm to town, In a loaded truck.on return journey he is able to travel 30km\h faster having unloaded his truck.he saves 1hour on return journey by travelling faster.\r
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\n" ); document.write( "\n" ); document.write( "Under journey ke:from farm 2 town\r
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\n" ); document.write( "distance,: 180km from farm to town \r
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\n" ); document.write( "\n" ); document.write( "Time: 180 over x\r
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Algebra.Com's Answer #740131 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "A man travels 180km from his farm to town, In a loaded truck.on return journey he is able to travel 30km\h faster having unloaded his truck.he saves 1hour on return journey by travelling faster. \r
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\n" ); document.write( "\n" ); document.write( "Table:
\n" ); document.write( "Under journey ke:from farm 2 town
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\n" ); document.write( "distance,: 180km from farm to town
\n" ); document.write( "Speed?
\n" ); document.write( "Time: 180 over x
\n" ); document.write( "From town to farm: distance??
\n" ); document.write( "Speed:x + 30
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document.write( "                    SPEED           TIME         DISTANCE\r\n" );
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document.write( "FARM to TOWN         x              180/x           180\r\n" );
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document.write( "TOWN to FARM        x+30           180/(x+30)       180\r\n" );
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document.write( "Difference                           1\r\n" );
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\n" ); document.write( "\n" ); document.write( "Find the speed of truck fully loaded when going from farm to town using \"180%2Fx-180%2F%28x%2B30%29=1\" and solve for x.\r
\n" ); document.write( "\n" ); document.write( "You can then use this to find the two times.
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