document.write( "Question 1123766: The width of a rectangle is three more than half the length. It’s perimetter cisb78 centimeters, find the length and width
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Algebra.Com's Answer #740126 by MathLover1(20850)\"\" \"About 
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let's the length be \"L\" and width \"W\"\r
\n" ); document.write( "\n" ); document.write( "if the width of a rectangle is three more than half the length, we have\r
\n" ); document.write( "\n" ); document.write( " \"W=L%2F2%2B3\"....eq.1\r
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\n" ); document.write( "\n" ); document.write( "if the perimeter is \"78\" centimeters, we have\r
\n" ); document.write( "\n" ); document.write( "\"2%28L%2BW%29=78\"....eq.2\r
\n" ); document.write( "\n" ); document.write( "substitute \"W\" from eq.1\r
\n" ); document.write( "\n" ); document.write( "\"2%28L%2BL%2F2%2B3%29=78\"...... solve for \"L\"\r
\n" ); document.write( "\n" ); document.write( "\"2L%2B2%28L%2F2%29%2B2%2A3=78\"\r
\n" ); document.write( "\n" ); document.write( "\"2L%2BL%2B6=78\"\r
\n" ); document.write( "\n" ); document.write( "\"3L=78-6\"\r
\n" ); document.write( "\n" ); document.write( "\"L=72%2F3\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28L=24%29\"\r
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\n" ); document.write( "\n" ); document.write( "go back to eq.1, substitute \"L\" and solve for \"W\"\r
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\n" ); document.write( "\n" ); document.write( " \"W=24%2F2%2B3\"....eq.1\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28W=15%29\"\r
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\n" ); document.write( "\n" ); document.write( "so, the length is \"24\" and width \"15\" centimeters \r
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