document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1123731>Question 1123731</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find two numbers such that if 18 is added to the first number, it becomes twice the second number and if 6 is added to the second number it becomes three times the first number  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #740122 by </B><A HREF=/tutors/aboutme.mpl?userid=LinnW><B>LinnW(1048)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=LinnW><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=LinnW><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=740122\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> f = first number<BR>\n" );
document.write( "s = second number<BR>\n" );
document.write( "18 + f = 2s<BR>\n" );
document.write( "6 + s = 3f<BR>\n" );
document.write( "subtract 6 to each side of the second equation<BR>\n" );
document.write( "s = 3f - 6<BR>\n" );
document.write( "substitute 3f - 6 for s in 18 + f = 2s<BR>\n" );
document.write( "18 + f = 2(3f - 6)<BR>\n" );
document.write( "18 + f = 6f - 12<BR>\n" );
document.write( "add 12 to each side<BR>\n" );
document.write( "12+18 + f = 6f - 12+12<BR>\n" );
document.write( "30 + f = 6f<BR>\n" );
document.write( "subtract f from each side<BR>\n" );
document.write( "30 = 5f<BR>\n" );
document.write( "divide each side by 5<BR>\n" );
document.write( "6 = f<BR>\n" );
document.write( "substitute 6 for f in s = 3f - 6<BR>\n" );
document.write( "s = 3(6) - 6<BR>\n" );
document.write( "s = 18 - 6<BR>\n" );
document.write( "s = 12<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );