document.write( "Question 1123686: a pulley with a radius of 10 inches is attached to a second pulley with a radius of 6 inches. Find the angle through which the smaller pulley turns as the 10-inch pulley makes two-thirds of a revolution. State your answer in radians and also in degrees rounded to the nearest hundredth. \n" ); document.write( "
Algebra.Com's Answer #740048 by greenestamps(13203)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "The rope moves along the circumferences of the two pulleys. \n" ); document.write( "The circumferences of the two pulleys are in the same ratio as the radii of the pulleys, 10:6 or 5:3. \n" ); document.write( "The angle through which the smaller pulley turns is then 5/3 of the angle through which the larger pulley turns. \n" ); document.write( "(5/3)*(2/3) = 10/9 \n" ); document.write( "The smaller pulley makes 10/9 of a turn. \n" ); document.write( "In radians that is (10/9)*2pi = 20pi/9; in degrees (10/9)*360 = 400. \n" ); document.write( " |