document.write( "Question 1123686: a pulley with a radius of 10 inches is attached to a second pulley with a radius of 6 inches. Find the angle through which the smaller pulley turns as the 10-inch pulley makes two-thirds of a revolution. State your answer in radians and also in degrees rounded to the nearest hundredth. \n" ); document.write( "
Algebra.Com's Answer #740047 by ikleyn(52814)\"\" \"About 
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document.write( "The two arcs for corresponding central angles must be of equal length:\r\n" );
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document.write( "    \"%282%2F3%29%2A%282%2Api%29%2A10\" = \"alpha%2A6\" inches  ====>\r\n" );
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document.write( "    \"alpha\" = \"%282%2F3%29%2A%282pi%29%2A10%2A%281%2F6%29\" radians = \"%2840%2F18%29%2Api\" = \"%2820%2F9%29%2Api\" radians = \"2\"\"2%2F9\".\"pi\" radians = 400 degrees.\r\n" );
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