document.write( "Question 1123667: a new community center is being built in pagosa springs. The perimeter of the rectangular playing field is 312 yards. the lenght of the field is 3 yards less than double the width. what are the dimensions of the playing field? \n" ); document.write( "
Algebra.Com's Answer #740023 by Boreal(15235)\"\" \"About 
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width=x
\n" ); document.write( "length=2x-3
\n" ); document.write( "Half the perimeter is L+W=156
\n" ); document.write( "so x+2x-3=156
\n" ); document.write( "3x=159
\n" ); document.write( "x=53 yards width
\n" ); document.write( "2x-3=103 yards length
\n" ); document.write( "2W=106
\n" ); document.write( "2L=206
\n" ); document.write( "it is 103 yards x 53 yards
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