document.write( "Question 101790: Lauren wants to mix 5 liters of 7% milk with skim- milk(0%fat) to produce a mixture of 2 46/47% milk. How much skim-milk should Lauren add? \n" ); document.write( "
Algebra.Com's Answer #74002 by stanbon(75887)\"\" \"About 
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Lauren wants to mix 5 liters of 7% milk with skim- milk(0%fat) to produce a mixture of 2 46/47% milk. How much skim-milk should Lauren add?
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\n" ); document.write( "Comment: Follow the fat
\n" ); document.write( "Also 2 46/47% = 0.0297
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\n" ); document.write( "7% solution DATA:
\n" ); document.write( "Amt = 5 liters ; amount of fat = 0.07*5 = 0.35 liters
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\n" ); document.write( "skim solution DATA:
\n" ); document.write( "Amt = x liters ; amount of fat = 0*x = 0 liters
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\n" ); document.write( "Mixture DATA:
\n" ); document.write( "Amt = 5+x liters ; amount of fat = 0.0297(5+x)=0.149+0.0297x liters
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\n" ); document.write( "EQUATION:
\n" ); document.write( "fat + fat = fat
\n" ); document.write( "0.35 + 0 = 0.149+0.0297x
\n" ); document.write( "0.32x = 0.149
\n" ); document.write( "x = 0.465 liters (amount of skim that should be added)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "
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