document.write( "Question 101793: Find two numbers whose sum is 62 and whose difference is 6. \n" ); document.write( "
Algebra.Com's Answer #73998 by Fombitz(32388)![]() ![]() You can put this solution on YOUR website! Let’s call the first number A, the second number B. \n" ); document.write( "(1) A + B = 62 \n" ); document.write( "(2) A – B = 6 \n" ); document.write( "Let’s use equation (2) to solve for B in terms of A and then we’ll substitute in equation (1) to solve for A. \n" ); document.write( "(2) A – B = 6 \n" ); document.write( "A – B + B = 6 + B Use the additive inverse of (-B) or B \n" ); document.write( "A = 6 + B Simplify \n" ); document.write( "-6 + A = -6 + 6 + B Use the additive inverse of (6) or -6 \n" ); document.write( "-6 + A = B or \n" ); document.write( "(3) B = A – 6. We’ll call that equation (3), that’s B in terms of A. Really it’s equation (2) re-arranged. \n" ); document.write( "Now let’s use this answer in equation (1) \n" ); document.write( "(1) A + B = 62 \n" ); document.write( "A + (A - 6) = 62 Plug in your value for B. \n" ); document.write( "2A - 6 = 62 \n" ); document.write( "2A – 6 + 6 = 62 + 6 Use the additive inverse of (-6) or 6 \n" ); document.write( "2A = 68 \n" ); document.write( "2A/2=68/2 Use the multiplicative inverse of (2) or 1/2 \n" ); document.write( "A=34 Use your answer for A in (1),(2), or (3) and solve for B. \n" ); document.write( "Let’s use (3), it’s most direct. \n" ); document.write( "(3) B = A – 6 \n" ); document.write( "B = 34 - 6 \n" ); document.write( "B = 28\r \n" ); document.write( "\n" ); document.write( "The answers are A=34, B=28. \n" ); document.write( " \n" ); document.write( " |