document.write( "Question 1123596: My second question is a rectangular picture with dimensions 5in by 8in is surrounded by a frame of uniform width. The combined area of the frame and picture is 180in squared find the width of the frame? Thank you for any help you can provide \n" ); document.write( "

Algebra.Com's Answer #739944 by solver91311(24713) $\"\"$ $\"About$

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\n" ); document.write( "\n" ); document.write( "Let

represent the width of the frame. Since there is a frame around all four sides, there are two of these

dimensions added to each of the length and width of the original picture, so the length with the frame is

, and the width with the frame is

, and since the total area is 180 in²:\r
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\n" ); document.write( "\n" ); document.write( "Multiply it out, put the equation in standard form, and solve the quadratic for the positive value of

. The negative root is discarded because a negative number for a measurement of length is nonsense.
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\n" ); document.write( "John
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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