document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=101735>Question 101735</A>: <I><SPAN STYLE=\"word-break: break-all;\"> x(.10)-[.12(10000-x)]=540 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #73991 by </B><A HREF=/tutors/aboutme.mpl?userid=Fombitz><B>Fombitz(32388)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Fombitz><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Fombitz><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=73991\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x(.10)-[.12(10000-x)]=540<BR>\n" );
document.write( "First off, let’s get rid of the decimals by multiplying both sides by 100.<BR>\n" );
document.write( "100(x(.10)-[.12(10000-x)])=100(540) Use the distributive property<BR>\n" );
document.write( "100x(.10)-100[.12(10000-x)]=54000<BR>\n" );
document.write( "100x(.10)-100[.12(10000-x)]=54000<BR>\n" );
document.write( "10x-[12(10000-x)]=54000 <BR>\n" );
document.write( "Start in the parentheses and work your way out. Use the distributive property. <BR>\n" );
document.write( "10x-[12(10000)-12x)]=54000 <BR>\n" );
document.write( "10x-[120000-12x)]=54000 <BR>\n" );
document.write( "10x+(-1)[120000-12x)]=54000 Use the distributive property again.  <BR>\n" );
document.write( "10x+(-120000)+12x=54000<BR>\n" );
document.write( "22x+(-120000)+120000=54000+120000 Use additive inverse of (-120000) or 120000.<BR>\n" );
document.write( "22x=174000    <BR>\n" );
document.write( "22x/22=174000/22 Use multiplicative inverse of (22) or 1/(22).<BR>\n" );
document.write( "x=174000/22=87000/11 Simplify.<BR>\n" );
document.write( "x~7909.1 Approximate answer.<BR>\n" );
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