document.write( "Question 1123535: The sum of the measures of two complementary angles exceeds the difference of the measures of their supplements by 32 degrees. Find the measure of each angle. \n" ); document.write( "
Algebra.Com's Answer #739881 by rothauserc(4718)\"\" \"About 
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1) x + y = 90
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\n" ); document.write( "2) x + s1 = 180
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\n" ); document.write( "3) y + s2 = 180
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\n" ); document.write( "90 = s1 -s2 +32
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\n" ); document.write( "4) s1 - s2 = 90 - 32 = 58
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\n" ); document.write( "solve equation 2 and equation 3 for s1 and s2
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\n" ); document.write( "s1 = 180 - x
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\n" ); document.write( "s2 = 180 - y
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\n" ); document.write( "substitute for s1 and s2 in equation 4
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\n" ); document.write( "(180 - x) - (180 - y) = 58
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\n" ); document.write( "5) y - x = 58
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\n" ); document.write( "use equations 1 and 5, we have two equations in two unknowns
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\n" ); document.write( "solve equation 1 for y
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\n" ); document.write( "y = 90 - x
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\n" ); document.write( "substitute for y in equation 5
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\n" ); document.write( "90 - x - x = 58
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\n" ); document.write( "-2x = -32
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\n" ); document.write( "x = 16
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\n" ); document.write( "y = 90 - 16 = 74
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\n" ); document.write( "x = 16 degrees and y = 74 degrees
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\n" ); document.write( "s1 = 180 - 16 = 164 degrees
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\n" ); document.write( "s2 = 180 - 74 = 106 degrees
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\n" ); document.write( "x + y = 90 degrees
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\n" ); document.write( "s1 - s2 = 164 - 106 = 58 degrees
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\n" ); document.write( "Note 58 + 32 = 90 degrees
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