document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1123453>Question 1123453</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the height of a 9 inch candle changes at a rate of -2/3 inches per hour when it is burning how long will it take the candle to burn completely<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #739794 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=739794\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "The length of the candle in inches after \"h\" hours is 9-(2/3)h.<br><BR>\n" );
document.write( "The candle is burned completely when its length is 0.<br><BR>\n" );
document.write( "So solve the equation: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=9-%282%2F3%29h+=+0 ALIGN=MIDDLE  ALT=\"9-%282%2F3%29h+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<br><BR>\n" );
document.write( "Of course, you don't need to use formal algebra.  Just find how many \"2/3 of an inch\" there are in 9 inches.<br><BR>\n" );
document.write( "It might sound complicated because of the fraction.  But it's the same kind of calculation as if the candle were 14 inches long and burning at a rate of 2 inches per hour: (14 inches) divided by (2 inches per hour) = 7 hours.<br><BR>\n" );
document.write( "(9 inches) divided by (2/3 inch per hour) = ?? hours. </SPAN>\n" );
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