document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1123452>Question 1123452</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I've been wrapping my head around this for a while and would like an easier explanation to solving these functions. Thank-you.\r<BR>\n" );
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document.write( "Suppose that the functions p and q are defined as follows.\r<BR>\n" );
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document.write( "p(x)= x^2+9<BR>\n" );
document.write( "q(x)= &#8730;x+8\r<BR>\n" );
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document.write( "Find:\r<BR>\n" );
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document.write( "(p &#8728; q)(8) = <BR>\n" );
document.write( "(q &#8728; p)(8) =  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #739776 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=739776\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> p o q put q into wherever there is a x.  So the x^2 becomes (q's function^2) then add 9.<BR>\n" );
document.write( "sqrt(x+8)^2+9=x+8+9=x+17 and when x=8, the function equals 25\r<BR>\n" );
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document.write( "q o p put p into q wherever there is a x.  So the sqrt (x+8) becomes sqrt (x^2+9 then +8)<BR>\n" );
document.write( "sqrt(x^2+9+8)=sqrt(x^2+17), so when x=8 sqrt (81)=9 </SPAN>\n" );
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