document.write( "Question 1123392: In investing $6,950 of a couple's money, a financial planner put some of it into a savings account paying 4% annual simple interest. The rest was invested in a riskier mini-mall development plan paying 13% annual simple interest. The combined interest earned for the first year was $638. How much money was invested at each rate?
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Algebra.Com's Answer #739697 by jerryguo41(197)\"\" \"About 
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The system of equations:
\n" ); document.write( "1. A financial planner put some of it into a savings account paying 4% annual simple interest. The rest was invested in a riskier mini-mall development plan paying 13% annual simple interest. The combined interest earned for the first year was $638.\r
\n" ); document.write( "\n" ); document.write( "\".04%2AX%2B.13%2AY=638\"\r
\n" ); document.write( "\n" ); document.write( "2. investing $6,950 of a couple's money \r
\n" ); document.write( "\n" ); document.write( "\"X%2BY=6950\"\r
\n" ); document.write( "\n" ); document.write( "System:
\n" ); document.write( "\".04%2AX%2B.13%2AY=638\"
\n" ); document.write( "\"X%2BY=6950\"\r
\n" ); document.write( "\n" ); document.write( "Rewrite and Plug-In\r
\n" ); document.write( "\n" ); document.write( "\".04%2AX%2B.13%2AY=638\" && \"X=6950-Y\"
\n" ); document.write( "\".04%286950-Y%29%2B.13%2AY=638\"
\n" ); document.write( "\"278-0.04%2AY%2B0.13%2AY=638\"
\n" ); document.write( "\"-0.04%2AY%2B0.13%2AY=360\"
\n" ); document.write( "\"0.09%2AY=360\"
\n" ); document.write( "\"Y=360%2F0.09\"
\n" ); document.write( "\"Y=4000\"\r
\n" ); document.write( "\n" ); document.write( "\"X=6950-Y\"
\n" ); document.write( "\"X=6950-4000\"
\n" ); document.write( "\"X=2950\"\r
\n" ); document.write( "\n" ); document.write( "$4000 was invested in the risky mini-mall dev plan, while $2950 was invested in the savings account.
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