document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1123379>Question 1123379</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A survey found that women's heights are normally distributed with mean 63.2 in. and standard deviation  of2.7 in. The survey also found that men's heights are normally distributed with a mean 68.1 in. and standard deviation  of2.8. Complete parts a through c below.\r<BR>\n" );
document.write( "\n" );
document.write( "a) 98.37% Woman (z score was hard to find on both)<BR>\n" );
document.write( "b) 99.87% Men<BR>\n" );
document.write( "c) if the height requirements are changed to exclude only the tallest 5% of? the men and the shortest 5% of women, what are the new height requirements?\r<BR>\n" );
document.write( "\n" );
document.write( "how do you set up and work the problem to get the answer of at least 58.7 in  and at least 72.1in round to one place as needed\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #739669 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=739669\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 98.37% of women are at a z-score of 2.14, and 2.14*2.7 is 5.78, so the percentile is at 68.98 or 69.0 inches<BR>\n" );
document.write( "99.87% of men are at a z-score of 3.015, and 3.015*2.8 is 8.44, so the percentile is at 68.1+8.44 or 76.5 inches<BR>\n" );
document.write( "The tallest 5% of men are a z-score <1.645<BR>\n" );
document.write( "z*sd=4.61 in<BR>\n" );
document.write( "it would be men below 68.1+4.6 or 72.7 in.\r<BR>\n" );
document.write( "\n" );
document.write( "The shortest 5% of women are at a z-score of -1.645, and -1.645*2.7 is 4.4, so it would exclude those more than 4.4 inches shorter than 63.2 or shorter than 58.8 inches.\r<BR>\n" );
document.write( "\n" );
document.write( "The basic formula is z=(x-mean)/sd, and solve for the missing variable. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );