document.write( "Question 1123366: A ladder 25 feet long is leaning against the wall of a house. The base of the ladder is pulled away from the wall at a rate of 2 feet per second. What is the velocity of the top of the ladder when the base is given below?
\n" ); document.write( "a.) 20 feet away from the wall
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Algebra.Com's Answer #739661 by rothauserc(4718)\"\" \"About 
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Let the ladder be y feet above the ground and x feet from the wall
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\n" ); document.write( "use Pythagorean theorem
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\n" ); document.write( "x^2 + y^2 = 25^2
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\n" ); document.write( "take first derivative of each vaiable with respect to time
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\n" ); document.write( "1) 2x * dx/dt + 2y * dy/dt = 0
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\n" ); document.write( "we are given dx/dt = 2 feet per second
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\n" ); document.write( "we want to find dy/dt when the ladder is 20 feet from the wall(x=20)
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\n" ); document.write( "when x=20
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\n" ); document.write( "20^2 + y^2 = 25^2
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\n" ); document.write( "400 + y^2 = 625
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\n" ); document.write( "y^2 = 225
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\n" ); document.write( "y = 15 feet (we ignore the negative root, -15)
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\n" ); document.write( "now use equation 1
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\n" ); document.write( "(2 * 20 * 2) + (2 * 15 * dy/dt) = 0
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\n" ); document.write( "80 + (30 * dy/dt) = 0
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\n" ); document.write( "dy/dt = -80/30 is approximately -2.67
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\n" ); document.write( "the velocity of the top of the ladder is -2.67 feet per second
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\n" ); document.write( "the velocity is negative because the top of the ladder is sliding down the wall
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