document.write( "Question 1123353: A movie theater sold 8 adult tickets and 3 children tickets for $86 on Monday.The theater sold 12 adult tickets and 6 tickets for $132 on Tuesday. Find the price of an adult ticket and a children's ticket? \n" ); document.write( "
Algebra.Com's Answer #739651 by rothauserc(4718)\"\" \"About 
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let x be cost of an adult's ticket and y be the cost of a children's ticket
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\n" ); document.write( "we have two equations in two unknowns
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\n" ); document.write( "1) 8x+3y = 86
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\n" ); document.write( "2) 12x+6y = 132
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\n" ); document.write( "solve equation 2 for y
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\n" ); document.write( "subtract 12x from both sides of =
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\n" ); document.write( "6y = 132-12x
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\n" ); document.write( "divide both sides of = by 6
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\n" ); document.write( "y = 22-2x
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\n" ); document.write( "substitute for y in equation 1
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\n" ); document.write( "8x+3(22-2x) = 86
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\n" ); document.write( "8x+66-6x = 86
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\n" ); document.write( "2x = 20
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\n" ); document.write( "x = 10
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\n" ); document.write( "y = 22-2(10)
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\n" ); document.write( "y = 22-20 = 2
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\n" ); document.write( "x = 10 and y = 2
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\n" ); document.write( "cost of adult's ticket is $20 and cost of children's ticket is $2
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\n" ); document.write( "check the answers with the two equations
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\n" ); document.write( "1) 8x+3y = 86
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\n" ); document.write( "8*10 + 3*2 = 86
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\n" ); document.write( "80+6 = 86
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\n" ); document.write( "86 = 86
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\n" ); document.write( "2) 12x+6y = 132
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\n" ); document.write( "12*10 + 6*2 = 132
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\n" ); document.write( "120+12 = 132
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\n" ); document.write( "132 = 132
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\n" ); document.write( "the answers check with equations 1 and 2
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