document.write( "Question 1123331: Lacrosse. The perimeter of an NCAA men’s lacrosse field is 340 yd. The length is 50 yd longer than the width. Find the dimensions. \n" ); document.write( "

Algebra.Com's Answer #739625 by ikleyn(52799) $\"\"$ $\"About$

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document.write( "L + W + L + W = 340   yards   (the perimeter)\r\n" );
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document.write( "2L + 2W = 340\r\n" );
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document.write( "L + W = 340/2 = 170.\r\n" );
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document.write( "Substitute L = W + 50.\r\n" );
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document.write( "(W + 50) + W = 170\r\n" );
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document.write( "2W = 170 - 50 = 120\r\n" );
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document.write( "W = 120/2 = 60.\r\n" );
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document.write( "Answer.  The dimensions are  60 yd (width)  and  60 + 50 = 110 yd (length).\r\n" );
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