document.write( "Question 1123324: The length of a rectangle is
\n" ); document.write( "2
\n" ); document.write( " meters less than
\n" ); document.write( "2
\n" ); document.write( " times the width. The perimeter is
\n" ); document.write( "20
\n" ); document.write( " meters. Find the width.
\n" ); document.write( " \n" ); document.write( "

Algebra.Com's Answer #739619 by ikleyn(52810) $\"\"$ $\"About$

You can put this solution on YOUR website!
.
\n" ); document.write( "

\r\n" );
document.write( "We know that \r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "L + W = 10    <<<---===  10 = , half of the perimeter.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "We also know that  L = 2W - 2.   Substitute it into very first equation. You will get\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "(2W-2) + W = 10,   or\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "2W - 2 + W = 10,\r\n" );
document.write( "\r\n" );
document.write( "3W = 10 + 2 = 12  ====>  W = 12/3 = 4.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Answer.  The width is 4 meters.\r\n" );
document.write( "

\r
\n" ); document.write( "\n" ); document.write( "Solved.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

\n" );