document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=14879>Question 14879</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please help me solve: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+8x%5E2%2B10a-3=0+ ALIGN=MIDDLE  ALT=\"+8x%5E2%2B10a-3=0+\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #7396 by </B><A HREF=/tutors/aboutme.mpl?userid=jb007mi6><B>jb007mi6(53)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jb007mi6><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=7396\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> so factor by grouping<BR>\n" );
document.write( "8x^2-2x+12x-3=0<BR>\n" );
document.write( "so from the first two terms factor a 2x and from the second two terms factor a 3<BR>\n" );
document.write( "you get 2x(4x-1)+ 3(4x-1)=0<BR>\n" );
document.write( "factor 4x-1 from both terms<BR>\n" );
document.write( "(2x+3)(4x-1)=0<BR>\n" );
document.write( "set each term equal to 0<BR>\n" );
document.write( "2x+3=0 or 4x-1=0<BR>\n" );
document.write( "x=-3/2 or 1/4 </SPAN>\n" );
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