document.write( "Question 1123204: A committee is to have 3 more women than men and the number on the committee must be at least 7 but no more than 15. What are the possible numbers of women on the committee? \n" ); document.write( "
Algebra.Com's Answer #739562 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! Start with 5W 2M \n" ); document.write( "6W3M \n" ); document.write( "7W4M \n" ); document.write( "8W5M \n" ); document.write( "9W6M \n" ); document.write( "x=women, y=men \n" ); document.write( "7<=x+y<=15, x=y+3 \n" ); document.write( "7<=2y+3<=15 \n" ); document.write( "4<=2y<=12 \n" ); document.write( "2<=y<=6 \n" ); document.write( "therefore, the women (y+3) can be 5,6,7,8,9 members. \n" ); document.write( " |