document.write( "Question 101608: One car travels 50 miles per hour and another one travels 55 miles per hour. If they start from the same place at the same time and travel in the same direction, after how many hours will the faster car be 35 miles ahed of the slower car? \n" ); document.write( "

Algebra.Com's Answer #73948 by ptaylor(2198) $\"\"$ $\"About$

You can put this solution on YOUR website!
distance(d)=rate(r) times time(t) or d=rt; r=d/t and t=d/r\r
\n" ); document.write( "\n" ); document.write( "Let t=number of hours that it takes the faster car to be 35 mi ahead of the slower car\r
\n" ); document.write( "\n" ); document.write( "Distance faster car travels=(rate of faster car)*t=55t\r
\n" ); document.write( "\n" ); document.write( "Distance slower car travels=(rate of slower car)*t=50t\r
\n" ); document.write( "\n" ); document.write( "Now the difference between these distances needs to equal 35 mi, so:\r
\n" ); document.write( "\n" ); document.write( "55t-50t=35
\n" ); document.write( "5t=35 divide both sides by 5\r
\n" ); document.write( "\n" ); document.write( "t=7 hours-------------ans\r
\n" ); document.write( "\n" ); document.write( "CK\r
\n" ); document.write( "\n" ); document.write( "in 7 hrs faster car travels 7*55 mi=385 mi
\n" ); document.write( "in 7 hrs slower car travels 7*50=350 mi\r
\n" ); document.write( "\n" ); document.write( "385-350=35
\n" ); document.write( "35=35\r
\n" ); document.write( "\n" ); document.write( "Hope this helps--ptaylor \n" ); document.write( "

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