document.write( "Question 1123148: Cody and Jeff both leave the park at the same time, but in opposite directions. If Jeff travels 7 mph faster than Cody and after 5 hours they are 105 miles apart, how fast is each traveling?
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Algebra.Com's Answer #739404 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! C=x mph \n" ); document.write( "J=x+7 mph \n" ); document.write( "in 5 hours, they go 5(x)+5(x+7)=105 miles apart \n" ); document.write( "5x+5x+35=105 \n" ); document.write( "10x=70 \n" ); document.write( "x=7 mph for Cody \n" ); document.write( "x+7=14 mph for Jeff \n" ); document.write( "That is 21 mph apart and 5 hours is 105 miles \n" ); document.write( " |