document.write( "Question 1123148: Cody and Jeff both leave the park at the same time, but in opposite directions. If Jeff travels 7 mph faster than Cody and after 5 hours they are 105 miles apart, how fast is each traveling?
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Algebra.Com's Answer #739404 by Boreal(15235)\"\" \"About 
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C=x mph
\n" ); document.write( "J=x+7 mph
\n" ); document.write( "in 5 hours, they go 5(x)+5(x+7)=105 miles apart
\n" ); document.write( "5x+5x+35=105
\n" ); document.write( "10x=70
\n" ); document.write( "x=7 mph for Cody
\n" ); document.write( "x+7=14 mph for Jeff
\n" ); document.write( "That is 21 mph apart and 5 hours is 105 miles
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