document.write( "Question 1123136: The length of a standard jewel case is 5 cm more than its width. The area of the rectangular top of the case is 266 cm squared.
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document.write( "What is the length and width of the jewel case? \n" );
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Algebra.Com's Answer #739384 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! The length of a standard jewel case is 5 cm more than its width. The area of the rectangular top of the case is 266 cm squared. \n" ); document.write( " \n" ); document.write( "What is the length and width of the jewel case? \n" ); document.write( "-------- \n" ); document.write( "Find a pair of factors of 266 that differ by 5. \n" ); document.write( "---- \n" ); document.write( "Or, if you prefer to spend more time on it: \n" ); document.write( "L = W + 5 \n" ); document.write( "L*W = 266 \n" ); document.write( "W*(W+5) = 266 \n" ); document.write( "W^2 + 5W = 266 \n" ); document.write( "W^2 - 5W - 266 = 0 \n" ); document.write( "Now, find a pair of factors of 266 that differ by 5. \n" ); document.write( " \n" ); document.write( " |