document.write( "Question 1123136: The length of a standard jewel case is 5 cm more than its width. The area of the rectangular top of the case is 266 cm squared.
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\n" ); document.write( "What is the length and width of the jewel case?
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Algebra.Com's Answer #739384 by Alan3354(69443)\"\" \"About 
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The length of a standard jewel case is 5 cm more than its width. The area of the rectangular top of the case is 266 cm squared.
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\n" ); document.write( "What is the length and width of the jewel case?
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\n" ); document.write( "Find a pair of factors of 266 that differ by 5.
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\n" ); document.write( "Or, if you prefer to spend more time on it:
\n" ); document.write( "L = W + 5
\n" ); document.write( "L*W = 266
\n" ); document.write( "W*(W+5) = 266
\n" ); document.write( "W^2 + 5W = 266
\n" ); document.write( "W^2 - 5W - 266 = 0
\n" ); document.write( "Now, find a pair of factors of 266 that differ by 5.
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