document.write( "Question 1123069: Need assistance please. Really, really lost. More than anything I would like to understand how to come to the solution. I have been working on this for quite some time.\r
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Algebra.Com's Answer #739290 by Edwin McCravy(20060)\"\" \"About 
You can put this solution on YOUR website!
\"%28%283x%5E4%29%2F%282y%5E%28-3%29%29%29%5E%28-3%29\"\r\n" );
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document.write( "First give the coefficient numbers 3 and 2 the exponent 1:\r\n" );
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document.write( "\"%28%283%5E1x%5E4%29%2F%282%5E1y%5E%28-3%29%29%29%5E%28-3%29\"\r\n" );
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document.write( "Now that every factor has an exponent, we remove the parentheses,\r\n" );
document.write( "by multiplying every exponent inside the parentheses by the exponent\r\n" );
document.write( "outside the parentheses.  [This is the distributive principle of\r\n" );
document.write( "exponents],\r\n" );
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document.write( "Simplify:\r\n" );
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document.write( "\"%283%5E%28-3%29x%5E%28-12%29%29%2F%282%5E%28-3%29y%5E9%29\"\r\n" );
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document.write( "Now use the rule for making negative exponents positive, which is\r\n" );
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document.write( "If there is a negative exponent on the TOP, move the base and\r\n" );
document.write( "exponent to the BOTTOM and change the sign of the negative\r\n" );
document.write( "exponent to positive.\r\n" );
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document.write( "and \r\n" );
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document.write( "If there is a negative exponent on the BOTTOM, move the base and\r\n" );
document.write( "exponent to the TOP and change the sign of the negative\r\n" );
document.write( "exponent to positive.\r\n" );
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document.write( "So we move the 3-3 from the top to the bottom and put 33 on the bottom.\r\n" );
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document.write( "We move the x-12 from the top to the bottom and put x12 on the bottom.  \r\n" );
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document.write( "And we move the 2-3 from the bottom to the top and put 23 on the top.\r\n" );
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document.write( "But we leave the y9 on the bottom because it already\r\n" );
document.write( "has a positive exponent.\r\n" );
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document.write( "\"%282%5E3%29%2F%283%5E3x%5E12y%5E9%29\"\r\n" );
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document.write( "We finish by raising 2 to the 3 power and getting 2∙2∙2 = 8,\r\n" );
document.write( "and raising 3 to the 3 power and getting 3∙3∙3 = 27:\r\n" );
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document.write( "\"8%2F%2827x%5E12y%5E9%29\"\r\n" );
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document.write( "Edwin
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