document.write( "Question 1122860: Label each of the following statements as true or false.\r
\n" ); document.write( "\n" ); document.write( "The graph of y=cos (θ+ pi/2) is a reflection of the graph of y= -sin θ in the x-axis.\r
\n" ); document.write( "\n" ); document.write( "On the interval -pi < θ < pi, the only intersection point of the graphs of y= θ amd y= sin θ is at 0=0.\r
\n" ); document.write( "\n" ); document.write( "2. Given the right triangle ABC, fill the values of sin θ and cos θ, and prove that sin^2 θ + cos^2 θ= 1
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Algebra.Com's Answer #739274 by Theo(13342)\"\" \"About 
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The graph of y=cos (θ + pi/2) is a reflection of the graph of y= -sin θ in the x-axis. \r
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\n" ); document.write( "\n" ); document.write( "i would say false.\r
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\n" ); document.write( "\n" ); document.write( "these equations are identical.\r
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\n" ); document.write( "\n" ); document.write( "if theta = pi/4 (45 degrees), then:\r
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\n" ); document.write( "\n" ); document.write( "cos(pi/4 + pi/2) = -.7071067812\r
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\n" ); document.write( "\n" ); document.write( "= sin(pi/4) = -.7071067812\r
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\n" ); document.write( "\n" ); document.write( "this occurs at all values of theta.\r
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\n" ); document.write( "\n" ); document.write( "the equations of y = cos(theta + pi/2) and y = sin(theta) would be reflections about the line = x.\r
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\n" ); document.write( "\n" ); document.write( "the following graphs show the relationships.\r
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\n" ); document.write( "\n" ); document.write( "in both graphs, i used x instead of theta, since x can be graphed easier than theta.\r
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\n" ); document.write( "\n" ); document.write( "theta and x mean the same thing.
\n" ); document.write( "they are the angle being measured.\r
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\n" ); document.write( "\n" ); document.write( "first graph is y = cos(x + pi/2) and y = -sin(x)\r
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\n" ); document.write( "\n" ); document.write( "both equations give you the same graph which means the equations are equivalent.\r
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\n" ); document.write( "\n" ); document.write( "second graph is y = cos(x + pi/2) and y = sin(x).\r
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\n" ); document.write( "\n" ); document.write( "in this graph it is clear to see that the graph of y = sin(x) is a reflection of the graph y = cos(theta + pi/2) about the x-axis.\r
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\n" ); document.write( "\n" ); document.write( "On the interval -pi < θ < pi, the only intersection point of the graphs of y= θ amd y= sin θ is at 0=0.\r
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\n" ); document.write( "\n" ); document.write( "this statement is true as can be seen in the following graph.\r
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\n" ); document.write( "\n" ); document.write( "in the graph, x represents theta.
\n" ); document.write( "they mean the same thing.\r
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\n" ); document.write( "\n" ); document.write( "you can see that when x is 0, y = sin(x) is equal to 0 and y = x is also equal to 0.\r
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\n" ); document.write( "\n" ); document.write( "at any other point on the graph, y = x is not equal to y = sin(x).\r
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\n" ); document.write( "\n" ); document.write( "the graph would ahow all the intersection points between the two equations and only one is shown at x = 0.\r
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\n" ); document.write( "\n" ); document.write( "Given the right triangle ABC, fill the values of sin θ and cos θ, and prove that sin^2 θ + cos^2 θ= 1\r
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\n" ); document.write( "\n" ); document.write( "in triangle ABC, side a is opposite angle A, side b is opposite angle B and side c is opposite angle C.\r
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\n" ); document.write( "\n" ); document.write( "the hypotenuse of the triangle is the side opposite angle C which is the right angle in the triangle.\r
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\n" ); document.write( "\n" ); document.write( "by pythagorus, c^2 = a^2 + b^2\r
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\n" ); document.write( "\n" ); document.write( "that's a given.\r
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\n" ); document.write( "\n" ); document.write( "you also know that sin(A) = opposite / hypotenuse = a/c and cos(A) = adjacent / hypotenuse = b/c\r
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\n" ); document.write( "\n" ); document.write( "in sin(A) = a/c, you can solve for a to get a = c * sin(A).\r
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\n" ); document.write( "\n" ); document.write( "in cos(A) = b/c, you can solve for b to get b = c * cos(A).\r
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\n" ); document.write( "\n" ); document.write( "in the formula c^2 = a^2 + b^2, you can replace a with c * sin(A) and you can replace b with c * cos(A) to get:\r
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\n" ); document.write( "\n" ); document.write( "c^2 = (c*sin(A))^2 + (c*cos(A))^2\r
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\n" ); document.write( "\n" ); document.write( "this becomes:\r
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\n" ); document.write( "\n" ); document.write( "c^2 = c^2 * sin^2(A) + c^2 * cos^2(A)\r
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\n" ); document.write( "\n" ); document.write( "divide both sides of this equation by c^2 and you get:\r
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\n" ); document.write( "\n" ); document.write( "1 = sin^2(A) + cos^2(A)\r
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\n" ); document.write( "\n" ); document.write( "QED\r
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\n" ); document.write( "\n" ); document.write( "the definition of QED is:\r
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\n" ); document.write( "\n" ); document.write( "QED is an abbreviation of the Latin words \"Quod Erat Demonstrandum\" which loosely translated means \"that which was to be demonstrated\". It is usually placed at the end of a mathematical proof to indicate that the proof is complete.
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