document.write( "Question 1123036: Need assistance please.\r
\n" ); document.write( "\n" ); document.write( "The width of a rectangle is 6 feet shorter than its length. If its perimeter is 82 feet, what is its
\n" ); document.write( "width?\r
\n" ); document.write( "\n" ); document.write( "I set it up as follows:\r
\n" ); document.write( "\n" ); document.write( "82=2(x-6)+2x\r
\n" ); document.write( "\n" ); document.write( "Which gave me a solution of
\n" ); document.write( "47/2=x
\n" ); document.write( "23.5=x\r
\n" ); document.write( "\n" ); document.write( "I cannot figure out what to do next. \r
\n" ); document.write( "\n" ); document.write( "Thank you
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Algebra.Com's Answer #739249 by ikleyn(52799) $\"\"$ $\"About$

You can put this solution on YOUR website!
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document.write( "In your notations, x is the length (although it would be more logical to make it the width . . . )\r\n" );
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document.write( "82 = 2(x-6) + 2x   <<<---=== Correct !\r\n" );
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document.write( "Next steps should be:\r\n" );
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document.write( "41 = x - 6 + x\r\n" );
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document.write( "41 + 6 = 2x\r\n" );
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document.write( "47 = 2x\r\n" );
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document.write( "x = 47/2 = 23.5    <<<---=== it is your LENGTH\r\n" );
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document.write( "Then you should find the WIDTH:  W = 23.5 - 6 = 17.5.\r\n" );
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