document.write( "Question 1123011: If the second of three consecutive integers is subtracted from 147 the result is the first and third what are the integers \n" ); document.write( "

Algebra.Com's Answer #739219 by ikleyn(52858) $\"\"$ $\"About$

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\n" ); document.write( "If the second of three consecutive integers is subtracted from 147 the result is the $\"highlight%28sum%29\"$ of the first and the third.
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\n" ); document.write( "\n" ); document.write( " Notice how I edited your post in order for it makes sense.\r
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document.write( "Let n be the middle of the three consecutive integers.\r\n" );
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document.write( "The the three integers are (n-1), n and (n+1).\r\n" );
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document.write( "The sum of the first and the third integers is  (n-1) + (n+1) = 2n.\r\n" );
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document.write( "The condition says\r\n" );
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document.write( "    147 - n = 2n.\r\n" );
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document.write( "It is easy to solve:\r\n" );
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document.write( "    147 = 3n  ====>  n =  = 49.\r\n" );
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document.write( "Answer.  The integers are  48, 49 and 50.\r\n" );
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